$\frac{2}{3}$

$\frac{8}{21}$

$\frac{3}{7}$

$\frac{9}{22}$

B. $\frac{8}{21}$

Total number of balls = (8 + 7 + 6) = 21

Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.

Therefore, n(E) = 8.

P(E) = $\frac{8}{21}$