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18750 sq.m

37500 sq.m

40000 sq.m

48000 sq.m

B. 37500 sq.m

$Letlength=xmetres.\phantom{\rule{0ex}{0ex}}Thenbreadth=\left(\frac{60}{100}x\right)metres\phantom{\rule{0ex}{0ex}}=\left(\frac{3x}{5}\right)m\phantom{\rule{0ex}{0ex}}Perimeter=\left[2\left(x+\frac{3x}{5}\right)\right]m\phantom{\rule{0ex}{0ex}}=\left(\frac{16x}{5}\right)m\phantom{\rule{0ex}{0ex}}\therefore \frac{16x}{5}=800\phantom{\rule{0ex}{0ex}}x=\left(\frac{800\times 5}{16}\right)\phantom{\rule{0ex}{0ex}}=250\phantom{\rule{0ex}{0ex}}So,length=250m,breadth=150m\phantom{\rule{0ex}{0ex}}\therefore Area=\left(250\times 150\right){m}^{2}=37500{m}^{2}$