614

714

814

914

C. 814

In this type of questions, first we need to calculate the area of tiles. With we can get by obtaining the length of largest tile.

Length of largest tile can be obtained from HCF of length and breadth.

So lets solve this,

Length of largest tile = HCF of (1517 cm and 902 cm)

= 41 cm

Required number of tiles =

$\frac{Areaoffloor}{Areaiftile}\phantom{\rule{0ex}{0ex}}=\left(\frac{1517\times 902}{41\times 41}\right)\phantom{\rule{0ex}{0ex}}=814$

40 m

50 m

120 m

None of these

$5m*5m$

$10m*5m$

$15m*5m$

$20m*5m$

$153500{m}^{2}$

$152500{m}^{2}$

$153800{m}^{2}$

$153600{m}^{2}$

20000

23000

25000

26000

$84feet$

$88feet$

$85feet$

$89feet$

55 m

56 m

57 m

58 m

614

714

814

914

2400 sq.cm

2480 sq.cm

2560 sq.cm

None of these

15,000

15,500

15,600

16,500

$17meter$

$23meter$

$20meter$

$25meter$

27%

28%

29%

30%

3410

3420

3430

3440

$4:15$

$4:25$

$3:15$

$3:25$

$44\%$

$45\%$

$34\%$

$35\%$

200cm

150cm

180cm

100cm

110 cm

115 cm

120 cm

125 cm

46 sq.ft

81 sq.ft

126 sq.ft

252 sq.ft

18750 sq.m

37500 sq.m

40000 sq.m

48000 sq.m

$24cm$

$26cm$

$23cm$

$28cm$

${m}^{2}$

1520${m}^{2}$

2420${m}^{2}$

2480${m}^{2}$

25207 cm

7.1 cm

7.2 cm

7.3 cm

50 cm

64 cm

124 cm

120 cm