4

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

$44%$

$45%$

$34%$

$35%$

A. $44%$

Let original length = x metres and original breadth = y metres
Original Area=xy m2
New Length =120100x=65x
New Area=65x * 65y
New Area=3625xy
Area Difference=3625xyxy
=1125xy
Increase%=DifferenceActual * 100
=11xy25 * 1xy * 100
=44%

4

4

2400 sq.cm

2480 sq.cm

2560 sq.cm

None of these

4

4

4

18750 sq.m

37500 sq.m

40000 sq.m

48000 sq.m

4

4

3410

3420

3430

3440

4

614

714

814

914

4

The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is

$153500{m}^{2}$

$152500{m}^{2}$

$153800{m}^{2}$

$153600{m}^{2}$

4

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

$44%$

$45%$

$34%$

$35%$

4

27%

28%

29%

30%

4

The Diagonals of two squares are in the ratio of 2:5. find the ratio of their areas.

$4:15$

$4:25$

$3:15$

$3:25$

4

The diffrence between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m,then its area is:

1520 ${m}^{2}$

2420 ${m}^{2}$

2480 ${m}^{2}$

2520 ${m}^{2}$

4

46 sq.ft

81 sq.ft

126 sq.ft

252 sq.ft

4

55 m

56 m

57 m

58 m

4

200cm

150cm

180cm

100cm

4

50 cm

64 cm

124 cm

120 cm

4

20000

23000

25000

26000

4

110 cm

115 cm

120 cm

125 cm

4

7 cm

7.1 cm

7.2 cm

7.3 cm

4

40 m

50 m

120 m

None of these